Four-star cornerback recruit Lamont Wade, a 5-foot-9, 185-pound player from Clairton, Pennsylvania, has announced his top 10 schools. Wade, a class of 2017 player with over a dozen offers, will be deciding between Penn State, Tennessee, UCLA, Ohio State, Pittsburgh, Virginia Tech, Duke, Alabama, West Virginia and Mississippi State. That's three SEC programs, three ACC programs, two Big Ten programs, one Big 12 program and one Pac-12 program, for those counting.
Wade thanked all of the coaches who have offered in his note. He also noted that the list can change at any time.
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247 Sports has Wade crystal balled to Ohio State, for what it's worth. He's rated as the 72nd-best player in the country for his class.