The Milwaukee Bucks and the Detroit Pistons have reportedly agreed to a trade ahead of Thursday night's NBA Draft.
Milwaukee, seeking to create more cap space ahead of free agency, has reportedly traded veteran forward Tony Snell to Detroit.
ESPN NBA insider Adrian Wojnarowski first reported the trade.
"Milwaukee is trading Tony Snell to Detroit, league source tells ESPN," he reports.
Snell, 27, averaged 6 points, 2 rebounds and 1 assist per game for the Bucks during the 2018-19 season. The former New Mexico star has two years and roughly $24 million left on his contract.
Milwaukee had reportedly been offering draft compensation to teams willing to take on some of their contracts, with key players like Kris Middleton, Brook Lopez and Malcolm Brogdon set to hit free agency this summer.
The Bucks are reportedly including their first round pick in the deal.
The NBA Draft is set to begin at 7 p.m. E.T. on Thursday.
It'll be televised on ESPN.